pickBC, B/C . BC, B/C "Because" No categories: add yours Source: Internet slang 'BC, B/C' on video `|[1,bc,bc(b+c)],[1,ca,ca(c+a)],[1,ab,ab(a+b)]|=0` If a,b,c are in AP, show that ` (a(b+c))/(bc) , (b (c+a))/(ca), (c(a+b))/(ab)`, are also in AP. If ab+bc+ca=0 , find the value of (1/a^2 - bc) + (1/b^2 - ac) + (1/c^2 - ab). Polynomials class 9. If `a+b+c=0` , then `(a^2)/(b c)+(b^2)/(c a)+(c^2)/(a b)=?\ ` (a)0 (b) 1 (c) `-1` (d) 3 sort: relevance, mode: exact match, q: "BC, B/C", maxResults: 4, videoEmbeddable: true, videoSyndicated: true, safeSearch: strict, type: video Subscribe to: Internet SlangEnglish Slang Leave my opinion